10.2 Derivatives of sums

Let’s suppose we have a function f⁢(x)=q⁢(x)+r⁢(x)f(x)=q(x)+r(x), then the derivative of f⁢(x)f(x) is 66 6 Note that this relies on the property that the limit of two things added together is the same as the sum of the limits of the two things limx→a(z⁢(x)+q⁢(x))=limx→az⁢(x)+limx→aq⁢(x)\lim_{x\to a}(z(x)+q(x))=\lim_{x\to a}z(x)+\lim_{x\to a}q(x) Where z⁢(x)z(x) and q⁢(x)q(x) are any functions of xx whose limit is defined as x→ax\to a.

d⁢fd⁢x\displaystyle\frac{df}{dx} =limh→0f⁢(x+h)−f⁢(x)h\displaystyle=\lim_{h\to 0}\frac{f(x+h)-f(x)}{h} (10.11)
=limh→0q⁢(x+h)+r⁢(x+h)−q⁢(x)−r⁢(x)h\displaystyle=\lim_{h\to 0}\frac{q(x+h)+r(x+h)-q(x)-r(x)}{h} (10.12)
=limh→0q⁢(x+h)−q⁢(x)+r⁢(x+h)−r⁢(x)h\displaystyle=\lim_{h\to 0}\frac{q(x+h)-q(x)+r(x+h)-r(x)}{h} (10.13)
=limh→0q⁢(x+h)−q⁢(x)h+limh→0r⁢(x+h)−r⁢(x)h\displaystyle=\lim_{h\to 0}\frac{q(x+h)-q(x)}{h}+\lim_{h\to 0}\frac{r(x+h)-r(x% )}{h} (10.14)
=d⁢qd⁢x+d⁢rd⁢x\displaystyle=\frac{dq}{dx}+\frac{dr}{dx} (10.15)

That is to say that

dd⁢x⁢(a⁢(x)+b⁢(x))=dd⁢x⁢(a)+dd⁢x⁢(b)\frac{d}{dx}(a(x)+b(x))=\frac{d}{dx}(a)+\frac{d}{dx}(b) (10.16)